10x^2+38x+3=3+3x

Solution for 10x^2+38x+3=3+3x equation:

10x^2+38x+3=3+3x

We move all terms to the left:

10x^2+38x+3-(3+3x)=0

We add all the numbers together, and all the variables

10x^2+38x-(3x+3)+3=0

We get rid of parentheses

10x^2+38x-3x-3+3=0

We add all the numbers together, and all the variables

10x^2+35x=0

a = 10; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·10·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*10}=\frac{-70}{20}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*10}=\frac{0}{20}
=0
$